Buoyant Force Conceptual Question
A rectangular wooden block of weight W floats with exactly one-half of its volume below the waterline.(Figure 1)
PART A
What is the buoyant force acting on the block?
ANSWER = W
PART B
The density of water is 1.00 g/cm3 . What is the density of the block?
ANSWER = 0.50 g/cm3
PART C
Masses are stacked on top of the block until the top of the block is level with the waterline. This requires 20 g of mass. What is the mass of the wooden block?
ANSWER = 20 g
PART D
The wooden block is removed from the water bath and placed in an unknown liquid. In this liquid, only one-third of the wooden block is submerged. Is the unknown liquid more or less dense than water?
ANSWER = more dense
PART E
What is the density of the unknown liquid ρunknown ?
ANSWER = 1.5 g/cm3
how do you get 1.5 g/cm^3 for part E?
ReplyDeletep=m/v, then use this to find the volume of the wooden block which is
ReplyDelete0/5=1/v then V=40. times this by 1/3 because only one-third of the volume is submerged. then use weight=fbuoyant. which will cancel out the g's you will be left with 20=p*40/3. rearrange you will get 1.5 for p